Timeline for Get IV from Key, Clear and Cipher text in AES-256 CBC
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Nov 16, 2017 at 10:05 | vote | accept | katze | ||
| Nov 15, 2017 at 20:31 | comment | added | Maarten Bodewes♦ | @SEJPM This is commonly a question in crypto courses to test if the student understands the mode. This is why I left out the actual calculations and schematics. Usually there is not much use for retrieving the IV, especially if the plaintext is already known anyway. | |
| Nov 15, 2017 at 20:29 | history | edited | Maarten Bodewes♦ | CC BY-SA 3.0 |
added 35 characters in body
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| Nov 15, 2017 at 19:58 | comment | added | zaph | OK, I finally see. Thx! | |
| Nov 15, 2017 at 19:50 | comment | added | SEJPM | @zaph Maarten is talking about a straight decryption of the first block w/o involving any modes, so you don't need an IV, BTW Maarten, you may want to add some mathy formulas to your answer for illustration | |
| Nov 15, 2017 at 19:14 | history | answered | Maarten Bodewes♦ | CC BY-SA 3.0 |