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Timeline for Why does my attempt at RSA break?

Current License: CC BY-SA 3.0

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Mar 3, 2018 at 4:18 vote accept Phoenixdeath
Mar 3, 2018 at 4:18 comment added Phoenixdeath I see. So, when using RSA, $\phi$($q$) is only ($q$-1) when $q$ is prime. Thank you!
Mar 2, 2018 at 11:02 history edited fgrieu CC BY-SA 3.0
Polish
Mar 2, 2018 at 8:45 history answered Meir Maor CC BY-SA 3.0