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May 14, 2018 at 8:02 vote accept CommunityBot
May 13, 2018 at 21:56 answer added kodlu timeline score: 1
May 13, 2018 at 19:33 history tweeted twitter.com/StackCrypto/status/995748927713488896
May 13, 2018 at 17:08 comment added Future Security Two thoughts. (Sorry not a good day for math) 1. The difference between $2^x-1$ and $2^x$ isn't much for most $x$. 2. If the coefficients of an input bit is zero for all output bits then your linear approximation is definitely not invertible, like a block cipher should be. A similar argument probably applies to the inverse. I'm thinking of an n by m matrix of zeros and ones as a representation of a linear XOR function. A row of all zeros or column of all zeros might correspond the $-\space1$s. There are more non-invertible matrices though, so I think it's just an upper bound.
May 13, 2018 at 14:34 review First posts
May 13, 2018 at 17:28
May 13, 2018 at 14:33 history asked user58612 CC BY-SA 4.0