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Jul 25, 2018 at 14:56 comment added SEJPM @zetaprime I have expanded my explanations in the parameters section accordingly.
Jul 25, 2018 at 14:55 history edited SEJPM CC BY-SA 4.0
addressed the questions from the comments
Jul 25, 2018 at 11:25 comment added SEJPM @zetaprime yes, if you use $\mathbb Z_p$ as your group then the exponentiation is indeed standard exponentiation modulo $p$. The matter of how to instantiate $H(\cdot,\cdot)$ is a bit more complex and I'll address it later.
Jul 24, 2018 at 23:01 comment added zetaprime I assume the exponentiation is simply the DH exponentiation with the same modulo p. However, I couldn't really understand the function H(.,.) with two arguments. Can I simply assume it's a hash with salt, which concatates the inputs given?
Jul 24, 2018 at 12:37 vote accept zetaprime
Jul 24, 2018 at 12:12 history answered SEJPM CC BY-SA 4.0