Skip to main content
polish
Source Link
kelalaka
  • 49.5k
  • 12
  • 118
  • 205

The answer is due to the Stevens et. al's workStevens et. al's work ;

They showed that, with an approximately $2^{39}$ calls to the MD5 compression function, it is possible, for any chosen $m_1$ and $m_2$, to construct $s_1$ and $s_2$ such that $\text{MD5} (m_1||s_1) = \text{MD5} (m_2||s_2)$.$$\text{MD5} (m_1\mathbin\|s_1) = \text{MD5} (m_2\mathbin\|s_2)$$

They also gave examples for colliding documents, software integrity checking, etc ...

The answer is due to the Stevens et. al's work.

They showed that, with an approximately $2^{39}$ calls to the MD5 compression function, it is possible, for any chosen $m_1$ and $m_2$, to construct $s_1$ and $s_2$ such that $\text{MD5} (m_1||s_1) = \text{MD5} (m_2||s_2)$.

They also gave examples for colliding documents, software integrity checking, etc ...

The answer is due to the Stevens et. al's work ;

They showed that, with an approximately $2^{39}$ calls to the MD5 compression function, it is possible, for any chosen $m_1$ and $m_2$, to construct $s_1$ and $s_2$ such that $$\text{MD5} (m_1\mathbin\|s_1) = \text{MD5} (m_2\mathbin\|s_2)$$

They also gave examples for colliding documents, software integrity checking, etc ...

The answer is due to the Stevens et. al's work.

They showed that, with an approximate expected calling of MDFapproximately $2^{39}$ calls to the MD5 compression function, thatit is $2^{39}$-timespossible, for any chosen $m_1$ and $m_2$ such, to construct $s_1$ and $s_2$ can be constructed to havesuch that $\text{MD5} (m_1||s_1) = \text{MD5} (m_1||s_1)$$\text{MD5} (m_1||s_1) = \text{MD5} (m_2||s_2)$.

They also gave examples for colliding documents, software integrity checking, etc ...

The answer is due to the Stevens et. al's work.

They showed that with an approximate expected calling of MDF compression function, that is $2^{39}$-times, for any chosen $m_1$ and $m_2$ such $s_1$ and $s_2$ can be constructed to have $\text{MD5} (m_1||s_1) = \text{MD5} (m_1||s_1)$.

They also gave examples for colliding documents, software integrity checking etc.

The answer is due to the Stevens et. al's work.

They showed that, with an approximately $2^{39}$ calls to the MD5 compression function, it is possible, for any chosen $m_1$ and $m_2$, to construct $s_1$ and $s_2$ such that $\text{MD5} (m_1||s_1) = \text{MD5} (m_2||s_2)$.

They also gave examples for colliding documents, software integrity checking, etc ...

typos
Source Link
kelalaka
  • 49.5k
  • 12
  • 118
  • 205

The answer is due to the Stevens et. al's work.

They showed that with an approximate expected calling of MDF compression function, that is $2^{39}$-times, for any chosen $m_1$ and $m_2$ such $s_1$ and $s_2$ can be constructed to have $\text{MD5} (m_1||s_1) = \text{MD5} (m_1||s_1)$.

They also gave examples for Collidingcolliding documents, Softwaresoftware integrity checking etc.

The answer is due to the Stevens et. al work.

They showed that with an approximate expected calling of MDF compression function, that is $2^{39}$-times, for any chosen $m_1$ and $m_2$ such $s_1$ and $s_2$ can be constructed to have $\text{MD5} (m_1||s_1) = \text{MD5} (m_1||s_1)$.

They also gave examples for Colliding documents, Software integrity checking etc.

The answer is due to the Stevens et. al's work.

They showed that with an approximate expected calling of MDF compression function, that is $2^{39}$-times, for any chosen $m_1$ and $m_2$ such $s_1$ and $s_2$ can be constructed to have $\text{MD5} (m_1||s_1) = \text{MD5} (m_1||s_1)$.

They also gave examples for colliding documents, software integrity checking etc.

Source Link
kelalaka
  • 49.5k
  • 12
  • 118
  • 205
Loading