Timeline for What are the values of $w$ such that the corresponding $\text{Keccak-}f[25w]$ function is invertible (bijective)?
Current License: CC BY-SA 4.0
4 events
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| Feb 13, 2019 at 6:37 | comment | added | lyrically wicked |
> Keccak can be inverted as long a the lane width is an even number < According to this answer, the function is invertible if $w$ is not a multiple of $15$. But, for example, $w=120$ is even, it is a multiple of $8$, and it is a multiple of $15$. Is the function invertible if |x| = 5, |y| = 5, |z| = 120?
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| Feb 11, 2019 at 4:27 | history | edited | banned | CC BY-SA 4.0 |
addressing a shift
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| Feb 6, 2019 at 8:04 | comment | added | lyrically wicked | > I’m assuming that you’re referring to changing the total number of lanes ($25$ as outlined in the standard) and not changing the 64-bit lanes size < No, the symbol $w$ denotes the lane size, and this question is about the invertibility of Keccak functions when $w=8, 16, 24, 32, 48, \ldots$, which corresponds to $\text{Keccak-}200, \text{Keccak-}400, \text{Keccak-}600, \text{Keccak-}800, \text{Keccak-}1200, \ldots$ The number of lanes is always the same ($25$). | |
| Feb 5, 2019 at 23:04 | history | answered | banned | CC BY-SA 4.0 |