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kelalaka
kelalaka
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I have aan RSA encryption with $e = 3$ , andpublic key $N$ (2048$(3,n)$ with 2048 bits) modulus $n$.

I want to find the value of the plaintext $m$ (plaintext), so that the cipherciphertext (in bytes representation) value endends with '\x00'+MySpesificString\x00+MySpesificString.

$cipher = pow(m,e,n)$$ciphertext = pow(m,e,n)$

withwhere $m$ iscan be any string, and cipher is "any string"+"\x00"+"MySpesificString"ciphertext has the following format

any string+\x00+MySpesificString

How iI can find the possible value of $m$?

I have a RSA encryption with $e = 3$ , and $N$ (2048 bits)

I want to find the value of $m$ (plaintext), so that the cipher (in bytes representation) value end with '\x00'+MySpesificString.

$cipher = pow(m,e,n)$

with $m$ is any string, and cipher is "any string"+"\x00"+"MySpesificString"

How i can find the possible value of $m$?

I have an RSA encryption with public key $(3,n)$ with 2048 bits modulus $n$.

I want to find the value of the plaintext $m$ so that the ciphertext (in bytes representation) value ends with \x00+MySpesificString.

$ciphertext = pow(m,e,n)$

where $m$ can be any string and ciphertext has the following format

any string+\x00+MySpesificString

How I can find the possible value of $m$?

added 13 characters in body
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kelalaka
kelalaka
  • 49.5k
  • 12
  • 119
  • 205

I have a RSA encryption with e = 3$e = 3$ , and N $N$ (2048 bits)

iI want to find the value of m $m$ (plaintext), so that the cipher (in bytes representation) value end with '\x00'+MySpesificString.

cipher = pow(m,e,n)$cipher = pow(m,e,n)$

with m$m$ is any string, and cipher is "any string"+"\x00"+"MySpesificString"

How i can find the possible value of m$m$?

I have a RSA encryption with e = 3 , and N (2048 bits)

i want to find the value of m (plaintext), so that the cipher (in bytes representation) value end with '\x00'+MySpesificString.

cipher = pow(m,e,n)

with m is any string, and cipher is "any string"+"\x00"+"MySpesificString"

How i can find the possible value of m?

I have a RSA encryption with $e = 3$ , and $N$ (2048 bits)

I want to find the value of $m$ (plaintext), so that the cipher (in bytes representation) value end with '\x00'+MySpesificString.

$cipher = pow(m,e,n)$

with $m$ is any string, and cipher is "any string"+"\x00"+"MySpesificString"

How i can find the possible value of $m$?

added 11 characters in body
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user81147
user81147
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I have a RSA encryption with e = 3 , and N. (2048 bits)

i want to find the value of m (plaintext), so that the cipher (in bytes representation) value end with '\x00'+MySpesificString.

cipher = pow(m,e,n)

with m is any string, and cipher is "any string"+"\x00"+"MySpesificString"

How i can find the possible value of m?

I have a RSA encryption with e = 3 , and N.

i want to find the value of m (plaintext), so that the cipher (in bytes representation) value end with '\x00'+MySpesificString.

cipher = pow(m,e,n)

with m is any string, and cipher is "any string"+"\x00"+"MySpesificString"

How i can find the possible value of m?

I have a RSA encryption with e = 3 , and N (2048 bits)

i want to find the value of m (plaintext), so that the cipher (in bytes representation) value end with '\x00'+MySpesificString.

cipher = pow(m,e,n)

with m is any string, and cipher is "any string"+"\x00"+"MySpesificString"

How i can find the possible value of m?

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user81147
user81147
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  • 1
  • 3