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when toggle format what by license comment
Aug 30, 2020 at 5:35 history edited fgrieu CC BY-SA 4.0
Fix
Aug 30, 2020 at 4:39 history edited fgrieu CC BY-SA 4.0
Polish
Aug 29, 2020 at 18:31 history edited fgrieu CC BY-SA 4.0
Polish
Aug 29, 2020 at 17:13 history edited fgrieu CC BY-SA 4.0
Fix. Simplify selection of 🄐 and 🄑 for search perposes; polish alignment.
Aug 29, 2020 at 16:18 history edited fgrieu CC BY-SA 4.0
Polish
Aug 29, 2020 at 16:07 history edited fgrieu CC BY-SA 4.0
Trim and polish
Aug 29, 2020 at 15:52 history edited fgrieu CC BY-SA 4.0
Typography
Aug 29, 2020 at 15:47 history edited fgrieu CC BY-SA 4.0
Typography
Aug 29, 2020 at 15:40 history edited fgrieu CC BY-SA 4.0
Number solutions, and simplify
Aug 28, 2020 at 6:03 history edited fgrieu CC BY-SA 4.0
Note similarity with Pohlig-Hellman cipher
Aug 27, 2020 at 20:40 history edited fgrieu CC BY-SA 4.0
Polish
Aug 27, 2020 at 20:34 history edited fgrieu CC BY-SA 4.0
Polish
Aug 27, 2020 at 20:21 history edited fgrieu CC BY-SA 4.0
Polish
Aug 27, 2020 at 20:08 history edited fgrieu CC BY-SA 4.0
Polish
Aug 27, 2020 at 19:45 history edited fgrieu CC BY-SA 4.0
Polish
Aug 27, 2020 at 19:18 comment added fgrieu @poncho: Yes. I've added that, and the conditions.
Aug 27, 2020 at 19:18 history edited fgrieu CC BY-SA 4.0
Polish
Aug 27, 2020 at 18:49 history edited fgrieu CC BY-SA 4.0
Polish
Aug 27, 2020 at 18:41 history edited fgrieu CC BY-SA 4.0
Improve
Aug 27, 2020 at 18:16 comment added poncho I believe that the answer you're trying to get to is, assuming $c$ is relatively prime to $pq$, then $c^e = m \bmod pq$ has either $\gcd( p-1, e ) \gcd( q-1, e )$ solutions or none. Complications that you've considered: what if $e$ is composite? What if both $p-1, q-1$ is not r.p. to $e$?
Aug 27, 2020 at 18:12 history edited fgrieu CC BY-SA 4.0
deleted 1 character in body
Aug 27, 2020 at 18:06 history answered fgrieu CC BY-SA 4.0