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Oct 23, 2020 at 20:00 vote accept Joël
Oct 22, 2020 at 20:42 answer added Myath timeline score: 2
Oct 22, 2020 at 14:35 history edited kelalaka CC BY-SA 4.0
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Oct 22, 2020 at 13:26 review First posts
Oct 22, 2020 at 13:55
Oct 22, 2020 at 13:20 comment added poncho By mirror pattern, do you mean that $x^2 \equiv (2^n-x)^2 \pmod{2^n}$? That's easy to show; $(2^n-x)^2 \equiv (-x)^2 \equiv (-1)^2x^2 \equiv x^2$
Oct 22, 2020 at 13:17 history asked Joël CC BY-SA 4.0