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Mar 26, 2021 at 11:35 comment added Andrea For Saber, the pk size is l * 256 * log(p) / 8 + 32, since the vector b is composed by l polynomials of 256 coefficients, of p bits each, and 32 is the size of the matrix A seed. For the ciphertext, another vector b' of size l * 256 * log(p) / 8 is generated, together with the message-encoding polynomial c_m which has 256 coefficients of T bits each. Note that for all security levels, p^10 and T=4. The only value that changes if l, ranging from 2 to 4.
Dec 22, 2020 at 19:41 comment added SEJPM @kelalaka because I couldn't figure out the formulas and didn't want to invest the time given that they also tabled the relevant values.
Dec 22, 2020 at 19:37 comment added kelalaka Why there are questions marks?
Dec 22, 2020 at 14:51 comment added Maarten Bodewes It took some time for me to realize that those keys sizes are in bytes, as I'm so used to bits for them - although bytes make more sense for encoding of keys. It's actually not as bad as I expected, other than McEliece starting off at around 261KB.
Dec 22, 2020 at 14:46 vote accept Maarten Bodewes
Dec 22, 2020 at 12:34 history answered SEJPM CC BY-SA 4.0