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Corrected phi calculation
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Adding on to the above, the modulus and public exponent can be extracted from the public.pem. The public exponent e is 10001.

It turns out that this is a constructed modulus which is very weak and was not generated using recommended security guidelines.

The 2048 bit, 617 decimal digit modulus N=pq can be factored immediately because it is a square. That's right p=q and N = p^2.

phi(N) = (p-1)xp(p-1)

HowThe method to find d the private exponent when e, p and q are known has been shown many times on this forum. Then the file can be decrypted.

Adding on to the above, the modulus and public exponent can be extracted from the public.pem. The public exponent e is 10001.

It turns out that this is a constructed modulus which is very weak and was not generated using recommended security guidelines.

The 2048 bit, 617 decimal digit modulus N=pq can be factored immediately because it is a square. That's right p=q and N = p^2.

phi(N) = (p-1)x(p-1)

How to find d the private exponent when e, p and q are known has been shown many times on this forum. Then the file can be decrypted.

Adding on to the above, the modulus and public exponent can be extracted from the public.pem. The public exponent e is 10001.

It turns out that this is a constructed modulus which is very weak and was not generated using recommended security guidelines.

The 2048 bit, 617 decimal digit modulus N=pq can be factored immediately because it is a square. That's right p=q and N = p^2.

phi(N) = p(p-1)

The method to find d the private exponent when e, p and q are known has been shown many times on this forum. Then the file can be decrypted.

Source Link

Adding on to the above, the modulus and public exponent can be extracted from the public.pem. The public exponent e is 10001.

It turns out that this is a constructed modulus which is very weak and was not generated using recommended security guidelines.

The 2048 bit, 617 decimal digit modulus N=pq can be factored immediately because it is a square. That's right p=q and N = p^2.

phi(N) = (p-1)x(p-1)

How to find d the private exponent when e, p and q are known has been shown many times on this forum. Then the file can be decrypted.