-1
$\begingroup$

I once asked a question "Would RSA make sense if we used no computers?". The answer was negative, because finding primes that would make secure keys would prove too hard. Assuming that we had found another way of finding primes without computers, would RSA be usable in, for example, medieval times?

$\endgroup$
7
  • $\begingroup$ As mentioned in the other thread, you would also need a good (hand-computable) hash function, since RSA is very malleable and you'd need a MAC. I think a more interesting version of your question is "Suppose SE.crypto is dropped into medieval times, and we need to communicate safely without the aid of any computers. What do we do? How does this change if we've brought plenty of massive primes with us?" $\endgroup$ Dec 8, 2013 at 17:46
  • $\begingroup$ Exponentiation without computers is still pretty annoying $\endgroup$ Dec 8, 2013 at 17:52
  • 1
    $\begingroup$ Something like Merkle Puzzles could be adapted to medieval tools. $\endgroup$ Dec 8, 2013 at 17:53
  • $\begingroup$ Why RSA? Using DH over a pregenerated elliptic curve or a pregenerated finite field should be faster and doesn't require per-key primes. $\endgroup$ Dec 8, 2013 at 17:55
  • 2
    $\begingroup$ It wouldn't. Having an alternate way of finding strong primes implies an oracle which reports on weak primes. And if you started talking about oracles in medieval times, encrypting data would be the least of your concerns. Joking aside, RSA would get increasingly hard to use as rivals factor bigger and bigger numbers. Clever substitutions were simple and effective, and you could have a dumb servant perform the task, instead of a mathematician. Here's more. $\endgroup$
    – rath
    Dec 9, 2013 at 0:45

1 Answer 1

2
$\begingroup$

Many of the beginner explanations use very simple examples: like this

It is still hard to factorize a small number by hand, compared to other operations. There is definitely a size of prime numbers where hand computation is still feasible, but hand factorizing isn't. Would you, for instance, even armed with a list of primes, be able to quickly tell me what the prime decomposition of 1043 is?

It's 149 and 7. Slow to decompose, but easy to multiple by hand. You can go a lot bigger by hand or with an abacus etc.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.