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I was wondering out of the functions (MD5, SHA-1, SHA-256, and SHA-512), do all provide 128-bit pre-image resistance and 128-bit second-image resistance?

Also, out of these hash functions, do only SHA-256 and SHA-512 provide 128-bit collision resistance? (Due to $l/2$ bits of security)

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Let first a table on the bit security.

Hash Rel. Year Pre-images Second Pre-images Collision Resistance Status
MD5 1992 128-bit 128-bit immediately broken compromised
SHA-1 1995 160-bit 160-bit broken compromised
SHA-256 2001 256-bit 256-bit 128-bit secure
SHA-512 2001 512-bit 512-bit 256-bit secure

While there is an attack on the pre-image of MD5 slightly less than the 128-bit that is given as $~2^{123.4}$, the actual cost is larger than the generic pre-image attack, so the pre-image is still non-broken. The collision resistance, on the other hand, is ultra fast, less than 5 minutes.

Remember that the multi-target attack on the pre-images makes any 128-bit output insecure.

SHA-1's collision resistance has been shuttered in practice and should not be used in practice anymore. Use at least 256-bit output hash functions like SHA-256, SHA3-256, Blake2b, or Shake series. This will help you secure from both classical and quantum attacks.

  • 23 February 2017, the Google team shuttered SHA-1 with $2^{63.1}$ SHA-1 evaluations and managed to produce two PDFs has the same SHA-1 hashes. This is an identical-prefix collision attack.

  • 24 April 2019, chosen-prefix collisions in approximately $~2^{68}$ SHA-1 evaluations by Leurent and Peyrin

The attack on SHA2-x is currently only possible on reduced rounds in which the researchers exhibit the power of their attack by reducing the rounds of the compression function.

For example; Bicliques for Preimages: Attacks on Skein-512 and the SHA-2 family works on 45 out of 64 with the complexity $2^{255.5}$ for pre-image attack on SHA-256. This means that if SHA-256 was designed as 45 rounds instead of 64, its pre-image resistance was broken with this attack. Fortunately, the standard doesn't reduce the rounds of SHAx series we always use them as full rounds.

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    $\begingroup$ @CryptoGuru: "The attack on SHA2-x is currently on possible in reduced rounds." means 'attacks on deliberately weakened variants of SHA2-x that we don't actually use in practice'. kelalaka knows this; however being more explicit in explaining what this means might not be a bad idea... $\endgroup$
    – poncho
    Commented Oct 26, 2022 at 15:44
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    $\begingroup$ What's the source for 150-bit SHA-1 Second Pre-images? $\endgroup$
    – fgrieu
    Commented Oct 26, 2022 at 16:50
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    $\begingroup$ @fgrieu nothing than my pure typo :) $\endgroup$
    – kelalaka
    Commented Oct 26, 2022 at 16:51

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