RSA, finding p,q [duplicate]

Question

If the public key $(e,n)$ and the private key $(d,n)$ are known, what is the easiest way to find the primes $p$ and $q$?

When $n$ and $\phi(n)$ are given this is easy to solve. But I can't manage it given just $(e,d,n)$.
Thanks for any help.

Answer 1

It's quite easy to find out the two primes $p$ and $q$ given the secret integer $d$ and the public modulus $n$ and the public exponent $e$.

An algorithm is found on the Appendix C of document SP800-56B.

I copy it here:

Appendix C: Prime Factor Recovery (Normative)

The following algorithm recovers the prime factors of a modulus, given the public and private exponents. The algorithm is based on Fact 1 in [Twenty Years of Attacks on the RSA Cryptosystem, D. Boneh, Notices of the American Mathematical Society (AMS), 46(2), 203 – 213. 1999. ].

Function call: RecoverPrimeFactors(n,e,d)

Input:

1. n: modulus

2.e: public exponent

3.d: private exponent

Output:1.(p,q): prime factors of modulus

Errors: “prime factors not found”

Assumptions: The modulus $n$ is the product of two prime factors $p$ and $q$; the public and private exponents satisfy $de ≡ 1 \, (\mod \lambda(n))$ where $λ(n) = LCM(p– 1,q– 1)$

Process:

1. Let $k = de – 1$. If $k$ is odd, then go to Step 4.
2. Write $k$ as $k= 2^tr$, where $r$ is the largest odd integer dividing $k$, and $t ≥ 1$.

3. For $i=1 \dots 100$ do:

   a. Generate a random integer $g \in [0, n−1]$.

   b. Let $y = g^r \mod n$.

   c. If $y= 1$ or $y = n– 1$, then go to Step g.

   d. For $j \in [1, t– 1]$ do:

     I. Let $x = y^2 \mod n$.
   
     II. If $x = 1$, go to Step 5.
   
     III. If $x =n– 1$, go to Step g.
   
     IV. Let $y=x$.
   

   e. Let $x=y^2 \mod n$.

   f. If $x = 1$, go to Step 5.

   g. Continue.

4. Output “prime factors not found” and stop.

5. Let $p = \gcd(y– 1, n)$ and let $q = n / p$.

6. Output $(p,q)$ as the prime factors.