# problem with “one time pad” [closed]

I am a french student and I read the post on the forums (How does one attack a two-time pad (i.e. one time pad with key reuse)?). I need your help if possible. I 'm 11 encrypted messages , all encrypted with the same key. How should I proceed?

message encrypted:

Message 1:

315c4eeaa8b5f8aaf9174145bf43e1784b8fa00dc71d885a804e5ee9fa40b16349c146fb778cdf2d3aff021dfff5b403b510d0d0455468aeb98622b137dae857553ccd8883a7bc37520e06e515d22c954eba5025b8cc57ee59418ce7dc6bc41556bdb36bbca3e8774301fbcaa3b83b220809560987815f65286764703de0f3d524400a19b159610b11ef3e

Message 2:

Message 3:

Message 4:

Message 5:

Message 6:

32510bfbacfbb9befd54415da243e1695ecabd58c519cd4bd2061bbde24eb76a19d84aba34d8de287be84d07e7e9a30ee714979c7e1123a8bd9822a33ecaf512472e8e8f8db3f9635c1949e640c621854eba0d79eccf52ff111284b4cc61d11902aebc66f2b2e436434eacc0aba938220b084800c2ca4e693522643573b2c4ce35050b0cf774201f0fe52ac9f26d71b6cf61a711cc229f77ace7aa88a2f19983122b11be87a59c355d25f8e4

Message 7:

32510bfbacfbb9befd54415da243e1695ecabd58c519cd4bd90f1fa6ea5ba47b01c909ba7696cf606ef40c04afe1ac0aa8148dd066592ded9f8774b529c7ea125d298e8883f5e9305f4b44f915cb2bd05af51373fd9b4af511039fa2d96f83414aaaf261bda2e97b170fb5cce2a53e675c154c0d9681596934777e2275b381ce2e40582afe67650b13e72287ff2270abcf73bb028932836fbdecfecee0a3b894473c1bbeb6b4913a536ce4f9b13f1efff71ea313c8661dd9a4ce

Message 8:

Message 9:

Message 10:

Message 11 a decrypter:

32510ba9babebbbefd001547a810e67149caee11d945cd7fc81a05e9f85aac650e9052ba6a8cd8257bf14d13e6f0a803b54fde9e77472dbff89d71b57bddef121336cb85ccb8f3315f4b52e301d16e9f52f904

## closed as off-topic by Maarten Bodewes♦, hunter, otus, DrLecter, ponchoOct 19 '14 at 20:21

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Requests for analyzing or deciphering a block of data are off-topic here, as the results are rarely useful to anyone else." – Maarten Bodewes, hunter, otus, DrLecter
If this question can be reworded to fit the rules in the help center, please edit the question.

In OTP you have $C=K\oplus{M}$. If the key is the same $C1=K\oplus M1$ and $C2=K\oplus M2$, => $C1 \oplus C2$ = $K\oplus M1 \oplus K\oplus M2$ = $M1 \oplus M2$ If you have the same ciphertext, that means that the same message was encrypted. E.g. messages 4,6,7,11 have the same first 6 symbols.