As part of an experiment, I was given a .enc RSA (encrypted) file that was most likely generated using openssl. I had the public key, I factored it, obtained the private exponent, and decrypted the .enc file in chunks of 64 bit. What I got as a result, was nonsense hex. I was supposed to get a password or secret key.
What I have so far:
Factors: 3917781347 x 4215069449
Private exponent: 9440767265896423601
Modulus: 16513720463601767803
I have used xxd to extract the hex data from the ciphertext file: xxd -p > enc.hex
This created a hex dump of the file called 'enc.hex'. The contents of this file begin like this:
7d4554292d7b9f980ed049cea0f968cf438b6fc312cf2028ce5ce2fe9f38
387b72a01bf6564f25884a2cacd187c2eeccd0cf78c2a74785f18d5e72b5
270ac3e45b6f7505347b38ec7684b1af206d73ea4a84cd59b50be56d7abf
74a569868406ab2b17846c9e448fe1392b21dac0b10fbb733536c99e598b
683be7400a1ad55c42faa171becd803b8b8f4a1fa512a33222ec042486c5
672f6200d4f00e2994b6d247a44edb6ce90795bde7ccda4433cf6fca8362
f87c68f9df6418c4f0b8fb9da39a1d173fea2b1466e646f01e2dc7fb0499
311d35ec75c15c5910b2d3e0c662de0b3b1716bab44faa2a36538bb44f6a
3c3abd37692cf95fa075b58485ad983533782d7bf51e10c0e3b18ccec972
My Python code:
#!/usr/bin/python
d = 9440767265896423601
N = 16513720463601767803
file = open('enc.hex', 'r')
c = file.read()
n = 16
c = c.replace('\n', '').replace('\r', '')
m = [hex(pow(int(c[i:i+n], 16), d, N)).rstrip("L") for i in range(0, len(c), n)]
f = open('decrypted.hex', 'w')
f.write(''.join(m))
f.close()
Where, 'c' is the ciphertext, 'd' is the private exponent, 'N' is the modulus and 'm' is supposed to contain the plaintext hex bytes.
Output of my python script:
0x2f2f7656414141410x41414141615155410x41416741414130670x6f414142464a4636
0x39746d3641414b530x4c3137624e3041410x41424a44414141410x412f365758484676
When I convert this to ASCII, I get nonsense:
//vVAAAAAAAAaQUAAAgAAA0goAABFJF69tm6AAKSL17bN0AAABJDAAAAA/6WXHFv
Also, '2F 2F' is not a Magic Number and does not indicate a file type. As I said, I was supposed to get a password one way or another after decryption.
I have spent weeks over this experiment, and I'm on the verge of crying now if I don't decrypt this and get the password to the next level.
Could someone please quickly verify what I've done is right, and they are getting the same hex sequence after decryption? Here are the files in a tarball:
http://www.filedropper.com/chaltar
Contents:
- .enc encrypted file
- .uyu (was a hint that .enc is encrypted in RSA 64 bit chunks; you can ignore it)
- .pem (a public key from where I extracted the modulus and public exponent)
UPDATE:
I understand what I need to do now, and I know what to expect. However, my Python code seems to be messing up the 64 bit block decryption somewhere near the end as I'm not getting the two '==' signs (3d 3d) at the end after decryption. This is the trail (end) hexdump of my decrypted file:
002ACD50 33 30 34 31 34 31 34 31 34 31 34 31 30 78 34 31 3041414141410x41
002ACD60 34 31 34 31 34 31 34 31 34 31 34 31 34 31 30 78 414141414141410x
002ACD70 34 31 34 31 34 31 34 31 34 31 34 31 34 31 34 31 4141414141414141
002ACD80 30 78 35 61 35 31 33 64 33 64 34 31 34 31 34 31 0x5a513d3d414141
002ACD90 34 31 30 78 30 410x0
The file unexpectedly ended with one byte (30). Could someone point out what is wrong with my python decryption code above?