I do not know much about cryptography. But, I'm in a situation where I need a hashing method that does not exhibit the avalanche effect. I tried Googling but couldn't find anything.

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    $\begingroup$ What's this hash for, and why don't you want the avalanche effect? $\endgroup$
    – cpast
    Commented May 18, 2015 at 16:57
  • $\begingroup$ Also, what security properties do you need from the hash? Collision resistance (we can't find two messages that hash to the same value)? Preimage resistance (given a value, we can't find a message that hashes to that value)? $\endgroup$
    – poncho
    Commented May 18, 2015 at 17:26
  • $\begingroup$ maybe sponge based hash functions are what you're looking for(ex.: SHA-3) $\endgroup$
    – SEJPM
    Commented May 18, 2015 at 17:42
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    $\begingroup$ Perfect Hash Functions might give you some direction to look. They aren't secure hashes at all, of course, but that's sort of what you're asking for, NOT having an avalanche means that there's information leakage. $\endgroup$ Commented May 18, 2015 at 18:20

1 Answer 1


In general, most hashing methods do not exhibit the avalanche effect:

In cryptography, my understanding is that failing the avalanche test makes a hash function vulnerable to many attacks that every cryptographic hash function is specifically designed to prevent. So every cryptographic hash function either exhibits the avalanche effect or is considered broken.

Are you looking for an example of a broken hash function to show students why this is such a bad thing? Or (what I would find more interesting) are you designing a system where this property would be useful in some way? I'd like to learn more about what you are trying to do.


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