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I am pentesting a database that where I found data which was base64 encoded. I tried the usual method of decoding base64, which didn't work.

Later, I found in database a field called base64_custom_key. How do I decrypt a base64 encoded message with a key?

For eg. The key looks like gP9jOzA75VyIW6FRuHZimQcLB1rCTKpGN8hdEXw0eY3kMx+/JDUntsob4a2qfSv and the value generated looks like ucaUCo4NmA88Tws8BoQsKAXdBcDn

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    $\begingroup$ This question clearly asks how to decrypt such a block of data guys, it only includes the block of data as example. I've seen this type of "encryption" before and I think it is valuable to explain that it's a substitution cipher and how to decrypt it. $\endgroup$
    – Maarten Bodewes ♦
    Nov 23 '15 at 7:24
  • $\begingroup$ I don't see the reason to put it on hold. Moderators, care to explain? This isn't about analyzing a specific cipher. $\endgroup$
    – ramailo sathi
    Nov 23 '15 at 18:26
  • $\begingroup$ I think the fact that this is a classical substitution cipher that has been applied in modern time to perform some kind of obfuscation has something to do with it, Abhi. Taht's however not a good close reason. $\endgroup$
    – Maarten Bodewes ♦
    Nov 24 '15 at 14:39
  • $\begingroup$ I would look at this page....just input your information and you will get your results malwaretracker.com/decoder_base64.php $\endgroup$
    – grandfinalemike
    Dec 7 '15 at 15:56
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That's a simple substitution cipher. Base 64 uses the following alphabet A-Za-z0-9+/. Here A encodes 000000, B encodes 000001 etc. In your case the g encodes 000000, P encodes 000001 etc.

Instead of writing your own decoder for that you can simply take the ciphertext, iterate through the characters of the ciphertext and replace g with A, P with B etc. After that you should be able to use a regular base 64 decoder to do the work for you.

Don't replace multiple characters at a time or you'll run into trouble. Put the characters in a new string instead (if you map g to A while there are still other A characters left then your algorithm will certainly fail).

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  • $\begingroup$ Note that this should be considered "toy encryption". $\endgroup$
    – Maarten Bodewes ♦
    Nov 23 '15 at 3:01
  • $\begingroup$ Thank you so much for the answer. This clearly is a non standard way of encrypting something. :) $\endgroup$
    – ramailo sathi
    Nov 23 '15 at 4:53
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    $\begingroup$ Note that many programming languages / environments include a built-in tool for such character replacement, e.g. tr/// for Perl, strtr() for PHP, string.translate() for Python, etc. Many of these are modeled on the Unix command-line tool tr. In particular, to decode your example string using Unix tools, just run the command echo ucaUCo4NmA88Tws8BoQsKAXdBcDn | tr 'gP9jOzA75VyIW6FRuHZimQcLB1rCTKpGN8hdEXw0eY3kMx+/JDUntsob4a2qfSv' 'A-Za-z0-9+' | base64 -d. $\endgroup$
    – Ilmari Karonen
    Nov 26 '15 at 15:42
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    $\begingroup$ ...and, of course, the second argument to tr in my previous comment should be 'A-Za-z0-9+/'. For some reason, I accidentally left the / out. For that particular input string (which does not contain the letter v) the mistake makes no difference, but it could potentially corrupt other inputs. $\endgroup$
    – Ilmari Karonen
    Jan 23 '17 at 12:12

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