Is there a secret sharing scheme where secrets can be weighted, and that you need a total weight of $1$ to unlock the secret?

I know that you could, of course, just figure out every subset that has access to the secret and then do a XOR secret sharing scheme, but that isn't very efficient.

  • $\begingroup$ @RickyDemer I'm considering the general case, where this may not be the case. $\endgroup$ Feb 13, 2016 at 20:29


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