# how to decrypt AES CBC 256 : while you have the Key and the IV [closed]

I've been working on a forensics challenge , and I'm in the last step , i have an AES CBC 256 encrypted string and i need to decrypt it .. is there's and well known tool , or a script of some kind 'python' or 'C' ?

note : i find a python script for the AES but it doesn't include the CBC "IV"

this is what im trying to decrypt ..

KEY = 7869686966766E6C6F697570756E707100000000000000000000000000000000

IV = 6C7579796E6171726E7371627368616C

Encrypted data: N3xlOTgnywpPupc1VXbP9FbOXb1pK+S+CzQOo4KtqGz/hVMQ6ki6rNoBkKik733j

## closed as off-topic by yyyyyyy, fgrieu, otus, mikeazoFeb 21 '17 at 15:30

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Programming questions are off-topic even if you are writing or debugging cryptographic code. Unless your question is specifically about how the cryptographic algorithm or protocol works, you should look into asking on Stack Overflow instead." – yyyyyyy, otus, mikeazo
If this question can be reworded to fit the rules in the help center, please edit the question.

• You can use PyCrypto as follows: plaintext = AES.new(key, AES.MODE_CBC, iv).decrypt(ciphertext). – yyyyyyy Feb 21 '17 at 14:46
• Have you tried looking on google? extranet.cryptomathic.com/aescalc/index is the fourth link down and I didn't even include CBC in my search terms. – Maybe_Factor Feb 22 '17 at 5:46
• i did but its not giving anything meaningful – user7451333 Feb 22 '17 at 12:49
• �vSL��V%��Yȓ�PLo��ܩ�ƅL����_�YO����Ho�T_�& – user7451333 Feb 22 '17 at 12:49