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I was reading this (chapter 3.1) paper, and the author proposed this method to calculate the MEDP on 2-round AES:

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I cannot fully understand what he is doing but it seems like it iterating over all possible intermediate differentials that lead to (a,b). Is that really the case?

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  • $\begingroup$ Have you looked at Appendix A (it contains a proof, which may be helpful)? By the way, the authors are both female (use she, not he). $\endgroup$ – Aleph Mar 10 '17 at 18:36

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