# encode plaintext with ecb

I have a plaintext "DENKMAL" which I have to encode in the ECB mode with the block size = 1 character (whereby the assignment $A\leftrightarrow 0, B \leftrightarrow 1$, etc.)

Now I should find the ciphertext of the plaintext.
What I have done up to now is the following step:

 D E N  K  M  A L
3 4 23 10 12 0 11


But I have no idea how to proceed.

Well, in ECB mode you'll simply encrypt each block independently of the others with the same key and they build the correspond ciphertext blocks, which means for an encryption algorithm $E$ of block size $\ell$ and key $k$ that you end up with $C_i=E_k(B_i)$ for $B_i$ the ith block of your plaintext and where the $C_i$ represent the ith block of the resulting ciphertext.