# How to properly apply the AES Mixcolums?

I had searched a lot but I don't undestand how work the operation on binary (How to solve MixColumns). What I don't undestand is from where he catch 0001 1011 to do the XOR operation.

Can someone explain me? Thanks in advance for the replies.

Do you mean where we come up with 0001 1011 (also known as 0x1B)? That's actually mentioned in the answer:
Multiplying by $2$ is what your question is about: it is equivalent to shifting the number left by one, and then exclusiving-or'ing the value 0x1B if the high bit had been one (where, in case you're wondering, the value 0x1B came from the field representation)
That is, the $GF(2^8)$ representation that AES uses is a polynomial representation, based on the irreducible polynomial $x^8 + x^4 + x^3 + x + 1$; 0001 1011 (or 0x1B) are the lower 8 bits of that polynomial.