1
$\begingroup$
2519590847565789349402718324004839857142928212620403202777713783604366202070
           7595556264018525880784406918290641249515082189298559149176184502808489120072
           8449926873928072877767359714183472702618963750149718246911650776133798590957
           0009733045974880842840179742910064245869181719511874612151517265463228221686
           9987549182422433637259085141865462043576798423387184774447920739934236584823
           8242811981638150106748104516603773060562016196762561338441436038339044149526
           3443219011465754445417842402092461651572335077870774981712577246796292638635
           6373289912154831438167899885040445364023527381951378636564391212010397122822
           120720357

Is this number used for factoring challenge only? Lets say one day a VERY VERY lucky guy just GUESS the factor P and Q correctly will there be any security issue in the world. Is anyone using this particular RSA 2048 for anything?

My initial thought was that this number was extremely important but I guess it is just one of the many RSA 2048 out there. Cracking this one by luck doesnt mean much right?

$\endgroup$
1
$\begingroup$

Is this number used for factoring challenge only? Lets say one day a VERY VERY lucky guy just GUESS the factor P and Q correctly will there be any security issue in the world. Is anyone using this particular RSA 2048 for anything?

I don't believe so. On occasion, the need for a composite of unknown (to anybody) factorization comes up; someone might be using it for that. Such numbers are harder to generate than you might think; if you just select a random 2048 value, find that it is composite, and run ECM on it a bunch, well, you won't know whether running ECM a bit longer would find the factorization. Using one of the RSA challenge numbers would make sense in that case, but again, I don't know of anyone who's actually doing it.

On the other hand,

Cracking this one by luck doesnt mean much right?

While there isn't a great deal of significance to this specific number, if someone did manage to factor it, it would certain raise the issue whether other 2048 bit numbers were hard to factor (which, incidentally, is precisely why RSA generated their challenge numbers in the first place)

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.