I'm implementing DES, but I cannot understand example.
After initial permutation: 14A7D67818CA18AD
Plaintext is 64-bits hexadecimal, so each character is 4-bits. The first entry of IP(Initial Permutation) table is 58 which means 58-th binary number in the plaintext.
That number is 1 because 58-th binary number is in 3 which is before the last entry 6. Anyway, it means first binary number in plaintext after IP must be 1!
Then, how can 1 is appeared? First hex must be
1*** and it means greater than equal to 8!! What I'm wrong with this?