So I'm trying to solve this problem. enter image description here

There are of course more but I'm trying to figure out how would I even solve this first one in order to do the rest. Any hints or help in the steps would be appreciated. I'm literally out of ideas.

  • 2
    What have you tried? – fkraiem Oct 15 at 4:30
  • 2
    Hint: your main options are, for each hash function considered, to A) prove that $H_i$ is not preimage resistant, by exhibiting (an algorithm that finds) a collision, that is $(x_0,y_0)$ and $(x_1,y_1)$ with $H_i(x_0,y_0)=H_i(x_1,y_1)$; in the process (algorithm) that finds $(x_0,y_0)$ and $(x_1,y_1)$ it can be be used $E$ and $E^{-1}$ as a black box. B) prove that $H_i$ is preimage resistant, by proving that any algorithm that finds a collision (as in A) could be turned into an algorithm that breaks $E$ (that is distinguishes it from an ideal cipher). – fgrieu Oct 15 at 6:07

The only chance you have here is either:

  • show that it is not preimage-resistant, i.e. how you could, given a value $h$ find a preimage $(x,y)$ with $H(x,y) = h$. Using the structure of the hash-function might help here.

  • reduce the preimage-resistance to some property of its constituents, here the block cipher. So, show that if you have some machine (function) $\tilde H_1$ which, for an input $h$ gives you a preimage $(x,y) = \tilde H_1(h)$ with $H_1(x,y) = h$, you can construct a machine which violates some of the properties of an ideal block cipher (like allowing to find a key or plaintext from ciphertext, or something similar – look for your definition of ideal block cipher). (This likely won't work for $H_1$, but might work for some of the other ones.)

For all of the non-broken real-world hash functions, unfortunately we can't do any of those, because we don't have ideal ciphers.

$H_1 (x,y) = E_y(y) \oplus x$

Hint;

$H_1( E_y(y) \oplus x ,y)= ?$

More Hint;

$H_1( E_y(y) \oplus x ,y)= E_y(y) \oplus E_y(y) \oplus x = x$

conclusion?

  • -1 This is not a complete answer and would probably be better written as a comment, as fgrieu has done for example. While hints may be useful to a single person, they are decidedly not useful to others who may visit this site with the same question and do not want just a hint. – forest Oct 16 at 22:33
  • @forest On the other hand, we are not a homework service, so arguably we should not provide full answers to such homework problems. – fkraiem Oct 17 at 2:55
  • @fkraiem We do answer questions even if they are homework questions, if they are well-researched. If they are not, then the correct course of action is to close the question, not to write a comment as an answer. – forest Oct 17 at 3:07
  • @forest and fkraiem Noted. Thanks. – kelalaka Oct 17 at 8:40

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