Encrypting AES in ECB mode

I'm fairly new to cryptography and am starting to understand this weird art of Mathematics and theory. One thing I am trying to understand and do is encrypting a plaintext into ciphertext using AES in ECB mode. For example, I want to encrypt the following plaintext: "Lucozade".

Would be great if someone could help me out with this as I am not sure how to integrate AES in ECB mode.

• You are trying to do this by hand or with software? – mikeazo Oct 31 '18 at 15:26
• divide the plaintext into 128 blocks, say $P=p_1,p_2,\ldots\,p_2$ encrypt each by $c_i = E_k(p_i)$, Note that, your plaintext may not be 0 mode 128 than you need a padding. fill 1 and rest 0 will be enough. note 2: ECM mode is not secure. – kelalaka Oct 31 '18 at 15:26
• Where do you get stuck? – Thomas M. DuBuisson Oct 31 '18 at 15:30
• Yeah I'm trying to do by hand to visually see how it works – Benza Jackpuut Oct 31 '18 at 15:32
• OMG. you are trying to encrypt AES with the hand? Good luck for you not having an error. this video might help you. – kelalaka Oct 31 '18 at 15:52