In effect the same 128 bit key is XORed at every round and before and after as whitening.

Would it be 2^128?

What are the dangers of such a naive key schedule and does AES suffer from them?

Edit: Fair enough, slide attack is a problem. It doesn't explain however why there is a key schedule instead of round constants.

  • $\begingroup$ I believe it would be no better than AES with a single round (i.e. trivially breakable). $\endgroup$
    – forest
    Nov 11 '18 at 3:46
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    $\begingroup$ I believe it will be under slide attack , unless you add round constant $\endgroup$
    – hardyrama
    Nov 11 '18 at 6:04
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    $\begingroup$ I've just added two other questions to the duplicate list, does this answer your updated question? $\endgroup$
    – SEJPM
    Nov 11 '18 at 20:20