The RSA encryption that you seem to be using is specified in PKCS#1, I've linked to the latest version, 2.2:
rsaEncryption OBJECT IDENTIFIER ::= { pkcs-1 1 }
where
pkcs-1 OBJECT IDENTIFIER ::= {
iso(1) member-body(2) us(840) rsadsi(113549) pkcs(1) 1
}
with the description:
The object identifier rsaEncryption (see Appendix A.1) identifies the
RSAES-PKCS1-v1_5 encryption scheme. The parameters field associated
with this OID in a value of type AlgorithmIdentifier SHALL have a
value of type NULL. This is the same as in PKCS #1 v1.5.
So your application is using PKCS#1 v1.5 padding. Attacks on textbook/plain/raw RSA - which you mention in your comment - are therefore not possible.
PKCS#1 is secure for static text, but it may be vulnerable to the Bleichenbacher attack that uses a padding oracle to try and find the message - in this case undoubtedly the secret key that is used to encrypt the actual data.
However, you've indicated that your ciphertext is signed. If we assume that this signature is correctly verified (and you'd be amazed how many times it is not) then this attack is not possible.
Of course, signing the ciphertext also has drawbacks: the encryption is lost for the plaintext message. More importantly, the scheme is not protected against the removal of the signature or the replacement of signatures. So an adversary can try and show that the message is theirs by simply substituting his own signature.
Signature substitution sounds horrible, but it may not be a problem if only signatures are accepted from one or more specific, trusted parties. In that case substituting the signature will simply result in the message being rejected by the receiving party (who hopefully knows what to do when receiving such message).
Conclusion: I would deem the current scheme secure. The fact that RSA PSS is used for signing gives hope that the person creating the scheme knew what she was doing. There seems to be no pressing need to implement OAEP instead.