How many oracle calls to break an affine cipher in a chosen plaintext attack?

Assuming the ability to launch Chosen Plaintext Attacks (CPA), how many oracle calls does an attacker need to break the affine cipher? How does it work?

• What happens if the attacker asks the oracle to encrypt $x = 0$? – Thomas Feb 25 '13 at 9:13

The answer is 1 I think because if we apply a chosen plain text attack, then we need at least 2 encrypted alphabets and two plaintext alphabets corresponding to the related encrypted alphabets. Then we will have two variable and two equations.