# AES-128 8th round bit fault propagation

It's well known that by injecting a byte fault during the 8th round of AES 128 just before the mix column the key can be recovered with $$2^{32}$$-key space. A brute force attack is then possible but it takes some time.

If instead a byte fault, it is just a bit flip does it reduce the key space for K10? And why?

In fact I was wondering if there is a kind of propagation of a 1 bit diff between the 8th round and 9th round that could reduce the key space for K10

• If you do a search on the web you'll find a lot of papers describing such kind of attack. – Von k Jan 1 at 16:58
• For instance this one: eprint.iacr.org/2009/575.pdf – Von k Jan 1 at 17:08
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