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In the Scheme Based on the SDH Assumption (page 11 of the paper https://link.springer.com/content/pdf/10.1007%2F978-3-540-28628-8_14.pdf), how does the commitment get revealed with the master trapdoor x?

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  • $\begingroup$ Could you elaborate? As far as I understood, the knowledge of trapdoor is not necessary for revealing. It's required only for equivocating. $\endgroup$
    – ckamath
    Jun 9, 2019 at 14:45
  • $\begingroup$ What do u mean with equivocating? Isn't the master trapdoor used for someone, other than the sender, to know the committed message? $\endgroup$
    – Fiono
    Jun 9, 2019 at 15:14
  • $\begingroup$ Im asking how can u know a if you know x, mathematically. $\endgroup$
    – Fiono
    Jun 9, 2019 at 15:22
  • $\begingroup$ No, according to the paper the trapdoor is used to open a commitment to a message M with randomness R to another message M' and randomness R'. I'd read the full version of the paper since it is written a bit more formally. $\endgroup$
    – ckamath
    Jun 9, 2019 at 15:50

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