This is simply saying that if a cryptosystem has a functional composition that is
$$ h_{k}(x) = f_{k_1}(g_{k_2}(x)) $$
then you can find a key for single encryption that works as the double encryption.
For example: consider the permutation cipher where a permutation is a key. The permutations are forming a group, named permutation group, under the composition. Therefore, double encryption in permutation cipher is just another permutation, i.e. another key. Therefore you will not get a benefit.
To see this, let simplify the alphabet into 5 letters and let $P$ and $Q$ be two keys for a 5 letter permutation cipher:
$$P = \begin{pmatrix}1 & 2 & 3 & 4 & 5 \\2 & 4 & 1 & 3 & 5 \end{pmatrix} \text{ and } Q = \begin{pmatrix}1 & 2 & 3 & 4 & 5 \\ 5 & 4 & 3 & 2 & 1 \end{pmatrix}$$ The compositon of the two keys is
$$R =QP = \begin{pmatrix}1 & 2 & 3 & 4 & 5 \\4 & 2 & 5 & 3 & 1 \end{pmatrix}$$ and this is another permutation $R$, i.e. $R$ is a key that works as a single key.
Now turn back to DES:
Campbell and Wiener in 1992 showed that DES is not a group (paywalled) (and paywall-free). They showed that that the size of the
subgroup generated by the set of DES permutations is greater than $10^{2499}$. Therefore this value is far greater than potential attacks on DES which would exploit a small subgroup. As a result, DES has no such weakness. Actually, we will be surprised that a well-designed block cipher will be forming a group.
If there is such property that is the DES forms a subgroup of the permutation group then there exists a known-plaintext attack on DES that requires, on average $2^{28}$ steps showed by Judy H. Moore and Simmons (paywalled).
Also, forming a group will reduce the Triple-DES or more generally the multiple encryptions into single encryption.
The academical works on DES closure
‡ This work claimed to be
described briefly in a posting to sci.crypt on Usenet News, 1992 May 18. This needs a link!