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As the title states; Is there any risk from encrypting the key with itself? EG. $C = AES(K=K, M=K)$

I'd assume not; after all, how does having the key for a safe inside the safe make it easier to pick the lock?

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  • $\begingroup$ Here is a similar question for the block cipher AES. $\endgroup$
    – Maarten Bodewes
    Dec 4, 2019 at 21:14
  • $\begingroup$ @MaartenBodewes didn't see that one, and it and one of the answers below answer my question combined, so I'll select and mark as duplicate. $\endgroup$
    – Legorooj
    Dec 4, 2019 at 22:04

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