There are public key algorithmic differences for how PGP computes fingerprints and keygrips. For the v4 protocol, fingerprints are not exclusively computed from public keys while keygrips are. RFC 4880 makes no mention about keygrips.
After digging into code at 10 different places in the the libgcrypt from https://github.com/gpg/libgcrypt/blob/master/tests/keygrip.c, it is still a mystery as to how PGP keygrips are computed for ed25519 and curve25519.
Fortunately, the keygrip.c provides the two normative example test vectors:
1. ed25519: publicKey = 773E72848C1FD5F9652B29E2E7AF79571A04990E96F2016BF4E0EC1890C2B7DB, keygrip = 9DB6C64A38830F4960701789475520BE8C821F47 2. cv25519: publicKey = 918C1733127F6BF2646FAE3D081A18AE77111C903B906310B077505EFFF12740, keygrip = 0F89A565D3EA187CEA39332398F5D480677DF49C
Can someone provide the operations on the public keys prior to the sha1 hash that creates that creates the keygrip output? (Thanks in advance.)