Alice and Bob have agreed to use the Three Pass Protocol.
Alice chooses the encryption exponent
e_A = 101
Bob chooses the encryption exponent
e_B = 209
Now Alice and Bob send three encrypted messages: y1, y2, and y3 in this order.
Which of the following are possible solutions?
a. y1 = 471, y2 = 27, y3 = 14 is possible
b. y1 = 27, y2 = 471, y3 = 14 is possible
c. y1 = 471, y2 = 14, y3 = 27 is possible
d. y1 = 27, y2 = 14, y3 = 471 is possible