3
$\begingroup$

Although this question maybe looks silly, I have searched similar questions in this forum and googled it but got no desired answers.

IND-CCA security has already been deeply studied in public cryptography. And it is also known that some symmetric constructions (e.g. CBC model) are not IND-CCA secure (for example, see this chapter). However, I didn't find so many results about IND-CCA secure symmetric encryption. The only construction I found is the one provided by Desai in Crypto2000

I was wondering, are there any other well-known constructions of IND-CCA secure symmetric encryption (classical secure)?

Besides, could they still be easily converted to a post-quantum version (for example, by double the length of the secret key)?

Improve this question
$\endgroup$
3
  • 3
    $\begingroup$ Aren't authenticated encryption CCA-secure? $\endgroup$
    – DannyNiu
    Nov 28, 2020 at 6:19
  • 1
    $\begingroup$ Many thanks! I just realized that every authenticated encryption achieves CCA security. $\endgroup$
    – M.Z.
    Nov 28, 2020 at 7:29
  • $\begingroup$ What’s the intuition for every AEAD scheme having CCA? Simply that AEAD == no malleability which limits CCA flexibility? $\endgroup$
    – Woodstock
    Nov 30, 2020 at 10:51

1 Answer 1

Reset to default
3
$\begingroup$

In Authenticated Encryption, the authors explained the framework and constructions for Authentication Encryption in detail.

In particular, In Theorem 3.2 they stated that "INT-CTXT" security together with "IND-CPA" security implies "IND-CCA" security.

Then, they introduced a general approach to an "Encrypt-then-MAC" construction that achieves both "INT-CTXT" and "IND-CPA" security, which further implies "IND-CCA" security.

Lastly, thanks for the comment given by @DannyNiu.

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.