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I am trying to figure out how to complete RSA manually. I am trying to encode a simple block message (Mi). I used CrypTool to determine the encryption. When I "manually" computed the plaintext, I obtained a different number than what CrypTool provided. Can someone guide me? Am I doing the manual encryption for RSA correct?

RSA Manually

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  • $\begingroup$ What is the integer $A$? $\endgroup$
    – Ievgeni
    Jun 16 '21 at 15:03
  • $\begingroup$ It could be also $Z$... $\endgroup$
    – Ievgeni
    Jun 16 '21 at 15:09
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    $\begingroup$ there are many textbook RSA example on internet, please refer to them. your Z is called ${\phi(n)}$ . and public exponent e is chosen as ${1<e<\phi(n)}$, and private exponent d is selected such that ${ed \equiv 1(mod(\phi(n))}$ $\endgroup$
    – SSA
    Jun 16 '21 at 15:24
  • $\begingroup$ Just used the Cryptool Online RSA with your setup and got the $\color{red}{Red}$ numbers. What is your problem, then? $\endgroup$
    – kelalaka
    Jun 16 '21 at 18:20
  • $\begingroup$ @kelalaka Thank you for the online resource! When I used CrypTool RSA Encryption and input the text MI, I receive the following: Numbers input in base 10 format: 360 / Encryption into ciphertext: 11,807. Why is there only one number? $\endgroup$
    – Jame
    Jun 16 '21 at 23:50

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