There is a list where, using the coordinates of the x points, it was determined whether there are points in the curve
It can be seen that the generator according to the formula y ^ 2 = x ^ 3 + a * x + b
determined from the list GPoint = (Gx, Gy) # Generator Point
a= 0
b= 7
p= 115792089237316195423570985008687907853269984665640564039457584007908834671663
y^2 = x^3 + a * x + b # secp256k1
point (x,y)
point (1,29896722852569046015560700294576055776214335159245303116488692907525646231534)
point (2,69211104694897500952317515077652022726490027694212560352756646854116994689233)
point (3,94471189679404635060807731153122836805497974241028285133722790318709222555876)
point (4,40508090799132825824753983223610497876805216745196355809233758402754120847507)
point (5,0)
point (6,19112057249303445409876026535760519114630369653212530612662492210011362204224)
point (7,0)
point (8,91736135629086734185706894124002126994554994840140056297753929940646699135966)
point (9,0)
point (10,0)
.......
.......
.......
.......
etc
But I, on the contrary, need to determine by the list through the point y
that is
point (y, x)
Is it possible to do this?