5
$\begingroup$

For some encryption scheme $(\mathcal{E}, \mathcal{D})$:

In the definition of IND-CCA, the adversary $\mathcal{A}$ can access the decryption oracle $\mathcal{D}$. The deep reason of this setting is to make sure that our scheme is able to "protect the ciphertexts" (e.g. the integrity and authenticity).

So "protecting the ciphertexts" is what an IND-CPA secure scheme can not offer. And that's why IND-CCA is stronger than IND-CPA. Furthermore, IND-CCA2 allows $\mathcal{A}$ to make queries to $\mathcal{D}$ after $\mathcal{A}$ receives the challenge ciphertext $c^{*}$, which is so called "adaptive" query.

Then my question is:

  • How should we describe this distinctive ability of resisting adaptive queries in IND-CCA2, in a pellucid way ?

In other words, "random bits-like ciphertexts" leads to IND-CPA security, "the protection of ciphertexts" leads to IND-CCA1 security. Then what leads to IND-CCA2 security?

Thanks in advance!

$\endgroup$
6
  • 2
    $\begingroup$ Does this answer your question? Easy explanation of "IND-" security notions? $\endgroup$
    – kelalaka
    Mar 25, 2022 at 10:27
  • 2
    $\begingroup$ "protect the ciphertexts" is very imprecise, I don't think such a definition is enlightening at all. $\endgroup$ Mar 25, 2022 at 12:09
  • 1
    $\begingroup$ Hi kelalaka and meshcollider ! I am aware of the definitions and security proofs of these models. So the content of that post is not very helpful to me. What I am looking for is some words to summarize the core differences between CCA1 and CCA2 in a short way just like "protect the ciphertexts "does (though it might not be that precise :-). Thus, this question is actually not an academic problem and doesn't have the standard answer. $\endgroup$
    – Max1z
    Mar 25, 2022 at 12:52
  • 1
    $\begingroup$ The issue is that you're understanding of CCA1 security is already flawed. "protecting the ciphertexts" as you phrase it is neither sufficient nor necessary for CCA1 security. $\endgroup$
    – Maeher
    Mar 25, 2022 at 16:16
  • 1
    $\begingroup$ CCA1 = Making decryption queries before seeing $c^*$ doesn't help you learn what's inside $c^*$; CCA2 = Making decryption queries before/after seeing $c^*$ doesn't help you learn what's inside $c^*$ $\endgroup$
    – Mikero
    Mar 25, 2022 at 17:42

1 Answer 1

5
$\begingroup$

IND-CCA1 is INDistinguishability under Chosen Ciphertext Attack.

IND-CCA2 is INDistinguishability under adaptive Chosen Ciphertext Attack.

In both, an adversary attempts to decipher a ciphertext $C$ by making queries to a decryption oracle that will decrypt anything. The difference is that in IND-CCA1, the queries are made without knowledge of $C$ (given to adversary after the queries), when in IND-CCA2 queries can be made with knowledge of $C$ (given to adversary early on, with prohibition to give $C$ to the decryption oracle).

IND-CCA1 models a decryption device temporarily made available to adversaries. IND-CCA2 makes that permanent.

Here are situations where IND-CCA2 encryption is desirable:

  • There's a server that decrypts, then parses the deciphered plaintext as a (message, signature) pair and checks it against a public key (unrelated to the encryption/encryption key). If OK, the server acts according to message; otherwise it outputs "I won't do " message.
  • Embassy A knows it's messages to B are intercepted by E and relayed (with the prefix INTERCEPT) encrypted to F; F deciphers then relays what starts with INTERCEPT to G, that A has penetrated. This puts A in an IND-CCA2 situation to attack the cipher from E to F (within the restriction that A can only submit messages starting with INTERCEPT).
  • There's a server that decrypts, then remove padding, and a timing attack allows to know how much padding was removed.
$\endgroup$
1
  • $\begingroup$ Very inspiring! The words "temporarily" and "permanently" are exactly what I want. Thanks! $\endgroup$
    – Max1z
    Apr 18, 2022 at 13:05

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.