# Questions tagged [rsa]

An asymmetric (e.g. public-key) cryptosystem, based on modular exponentiation with big exponents and modulus. RSA can be used both for signature and encryption with proper paddings.

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### Who first published the interest of more than two prime factors in RSA?

Multi-prime RSA is now a well known technique (described here): it uses $k>2$ distinct secret prime factors in the public RSA modulus, with the advantage that, using the CRT, we can gain a speed ...
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### Fewest qubits required for the discrete logarithm problem and integer factorization

According to a paper from 2002, the most efficient circuit to factor an $n$-bit integer requires $2n+3$ qubits and $O(n^{3}\lg(n))$ elementary quantum gates, assuming ideal qubits. Later on, according ...
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### Name of an archaic type of RSA padding (0BBBBBBB…)

In some legacy code, I encountered RSA signature padding in the following format (hexadecimal): 0B BB BB BB BB BB BB ... BB BB <hash> Is there a name for ...
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### RSA key such that pi deciphers to your name per RSA-OAEP

Can you efficiently construct an RSA public/private key pair with $8k$-bit public modulus such that $C=\left\lfloor\pi\,2^{8k-2}\right\rfloor$ deciphers per RSA-OAEP to your name as a bytestring in ...
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### RSA factorization with special primes

Suppose that primes for RSA modulus are generated using formula: $P_i(x,y) = \operatorname{next\_prime}(x^{z_i}+y^{z_i}) = x^{z_i}+y^{z_i}+d_i$ where $x,y$ are unknown random numbers with size 128 ...
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### Are there attacks against broken RSA signature pad checking with $e = 65537$?

Let's say that an RSA implementation of PKCS #1 signatures fails to validate that the 00 01 FF FF FF ... FF 00 portion of the decrypted signature is exactly as long ...
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### Bleichenbacher RSA1024 signature forgery, closed-form solution

Hal Finney's writeup (Bleichenbacher's RSA signature forgery based on implementation error) shows a formula for RSA3072. I tried to replicate the attack for RSA1024 and failed, since the first term of ...
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### In RSA, given public key $(n,e)$ and $d^e\bmod n$, can we factor $n$?

Given an RSA public key $(n,e)$ and the textbook-RSA encryption $c$ of a valid matching private exponent $d$, computed as $c\gets d^e\bmod n$:Ā  can we factor $n$ ? Assume $n,e,d$ are per PKCS#1v2.2. ...
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### RSA like trapdoor permutations in Discrete logarithm

In RSA, given only $(n,e)$, where $n =pq$ and $e$ is the public exponent, it is hard to find $p$ and $q$. It also seems hard to find $d$. So we came up the RSA conjecture that is RSA defines a ...
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I've found a way to complete a task which I'd solve with passwords or by sending keys over the wire (otherwise) by using RSA's homomorphic property. I'm restricted to RSA (any padding; for hardware ...
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### Finding the period of a function with a single output qubit - impact on RSA

In this paper,May and Schlieper claim that one can find the period of a function $f()$ by embedding $h \circ f = h(f(x))$ for input $x$. This would have the immediate consequence of reducing the ...
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### Is there an efficient way to verify the union of two RSA accumulators?

More specifically, say we have one RSA accumulator $A_{S_1}$ accumulating set $S_1$ and another RSA accumulator $A_{S_2}$ accumulating set $S_2$. Does there exist a sublinear method to securely verify ...
259 views

### Decrypting small integers under RSA

Let $(n,e)$ be an RSA public key. Suppose $c = m^e \pmod n$, where $c>1$ is a very small integer. For concreteness, say $c=2$ or $c=4$. Is it hard to find $m$ under the RSA assumption (or any of ...
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### Source of very large prime numbers

The RSA cryptosystem makes use of $n=pq$ where $p, q$ are large prime numbers. With quantum computing, factorization might become easier, so it will probably be useful to use much much bigger $p$, $q$ ...
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### Where is RSA-KEM used as of 2020?

RSA-KEM is introduced by Yuliang Zheng and Jennifer Seberry 1992, Practical Approaches to Attaining Security against Adaptively Chosen Ciphertext Attacks and compared the security against OAEP ...
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### The security of blind RSA signatures with modular exponentiation as padding

It is known that (blind) RSA signature implementations should apply some sort of padding to messages before signing or blinding them. Does blind RSA signature with modular exponentiation as a padding ...
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### Why do one-way accumulators use rigid integers as the modulus?

In the paper that introduced one-way accumulators, the author's justify their use of rigid integers as the modulus with the following: The advantage of using a rigid integer $n = pq$ is that the ...
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### Private evaluation public quick verification VDF

Does anyone know of any VDF, that can be calculated by someone holding some private key in t sequential steps and is quickly verifiable in exponentially reduced step by anyone using some public key ...
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### RSA: Blinding versus fixed-time computation

For RSA, what is the standard solution against timing attacks? I know about RSA blinding as one solution. Another solution is to always compute both the squared value and square-and-multiply values, ...
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### Concept for a RSA “repeater”. Is it sensible?

I have been using RSA signed/encrypted mailing a lot recently. Naturally, I wanted to use RSA mailing also on my phone, not only on my computer. However, I feel uneasy having my private key on my ...
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### Using YubiKey to store a PIN-protected secret for disk encryption

I want to store a secret on YubiKey and use it for disk encryption. It's crucial that it be PIN protected. There are a limited number of PIN tries, and after three attempts the YubiKey would be ...
I have been reading up on RSA attacks and came across a problem that could be called a most-significant-bit (MSB) oracle attack. For the sake of clarity, let's define RSA primes $(p, q)$, private key ...