Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 56901

Elliptic curves are algebraic-geometric structures with applications in cryptography. Such a curve consists of the set of solutions to a cubic equation over a finite field equipped with a group operation. Questions relating to elliptic curves and derived algorithms should use this tag and might also consider more specific tags such as discrete-logarithm and ecdsa.

1 vote
2 answers
1k views

EC Calculations in Java

Just for the sake of learning, I'm attempting to write an ECDSA implementation in Java. I have what I believe is a correct implementation for point addition and doubling, but I'm not sure how to impl …
Lev Knoblock's user avatar
14 votes
1 answer
3k views

Why are Jacobian Coordinates used?

I couldn't find this explained in another question, but is there an actual reason as to why Jacobian coordinates are used for elliptic curves? Do they provide some sort of advantage in terms of perfor …
Lev Knoblock's user avatar
0 votes
1 answer
793 views

Birthday Attack against Cryptocurrency

One of my friends is creating his own cryptocurrency, just as a fun project, and he made some design choices that I think are insecure, but I personally don't have enough expertise to evaluate. Assum …
Lev Knoblock's user avatar
3 votes
1 answer
1k views

Schnorr Pubkey Recovery

As per How does recovering the public key from an ECDSA signature work?, it's possible to recover public keys from ECDSA signatures. Is this possible for EC-Schnorr signatures as well? I'm looking spe …
Lev Knoblock's user avatar