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A cryptographic hash algorithm is a function which takes a variable size input and produces a fixed size output. The algorithm makes it difficult to find two inputs with the same output or reconstruct the input from the output.

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How can I prove a truncated hash fuction need not be collision resistant?

Let $H : \{0, 1\}^∗ \mapsto \{0, 1\}^ n$ be a collision-resistant hash function. Define $H_0(M) = H(M)\mathbin\|0^{n−10}$. That is, $H_0$ appends ($n − 10$) zeros to the output of $H$. …
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