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Does using a block cipher in CBC mode *twice* result in an all-or-nothing transform (AONT)?

The below is the first pass with the encryption of CBC where key $k$ is public or $0$ and $nb$ is the number of blocks. We keep the IV as random number \begin{align} C_1 &= Enc_k(P_1 \oplus IV)\\ ...
kelalaka's user avatar
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2 votes

Indistinguishability versus Indifferentiability

The definitions of "indistinguishability" and "indifferentiability" were introduced in paper "Indifferentiability, Impossibility Results on Reductions, and Applications to the ...
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