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1

In general this is not possible. Assuming a finite group, for any $A$ in the group and for any $x$ in the group, the pair $(x,A-x)$ is a possible solution. You cannot do any better. If you have some side information which enables you test a value $x$ for being valid, you would at worst still need to test every $x$ in the group. This property follows from the ...


3

It seems that the question you're asking is about how to add a public (unmasked?) value to a secret-shared value. I suggest you edit the question a bit to clarify that this is not related to AES directly. With that aside, adding a public value to a secret-shared value depends heavily on what secret-sharing scheme you're using, and also the algebraic ...


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