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2

Assuming the first code extract is translated straightforwardly to machine code (perhaps by blocking some compiler optimizations, or using a relatively dumb compiler) and executed on a CPU that performs no groundbreaking runtime optimization, it it is plausible that execution time has no dependency on the data in the arrays, except perhaps in the final 0 == ...


0

Your problem is the min. Here is one way to make a constant time min if you have a constant time subtractor and adder, Let $Sub(x,y)$ be a constant time subtractor. Let $Add(x,y)$ be a constant time adder. Let $MSB(x)$ returns the sign bit. //Inputs x and y are arrays with length property //Returns the min of x and y in constant time constantTimeMin(x,y) ...


8

Constant-time multiplication in software without constant-time multiplier is easy. In C, this working code to compute $x\cdot y$ for 8-bit inputs is typically┬╣ constant-time: unsigned mul(unsigned char x, unsigned char y) { unsigned r = x, s = x&-(y&1); s += (r += r)&-((y >>= 1)&1); s += (r += r)&-((y >>= 1)&1); s +...


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