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@corpsfini Because ker([4]) ≅ Z4×Z4 , which leads to 5 subgroup of order 4. So these 5 cyclic groups have generator Pi, and [2]Pi is an order 2 point. So there is 5. Can you give me the way how you count this?
Thanks a lot for your patient explanation poncho. So what you're saying is that we're skeptical, but at the same time we can't strictly say that chaos-based cryptography is not quantum-resistant, in my opinion, because we still do not understand chaos systems well enough right?
Thanks for the links kodlu, widely used I mean I have seen a large amount of literature on this topic,sorry about my poor english. But I indeed do not know that whether chaos based cryptography is publicly accepted in practical. So the reason of lacking rigorous proof is what? Complexity or something else?