So i have a question to answer and i am a bit stuck, i have looked around the forum and web.
So we have q = 311$q = 311$, p = 163$p = 163$, e = 101$e = 101$, I found d = 39281$d = 39281$ using Euclidean Algorithm and checked by encrypting and decrypting a msgmessage.
Next it is asking if e = 101$e = 101$ was a good choice or would the value e = 9131$e = 9131$ be better.
101 = primeWhat I know:
39281 = not prime ( 23 x 397)
$101$ = prime
$39281$ = not prime ( $23 x\times 397$)
Both options for e$e$ are relatively prime to (p - 1) * (q - 1)
$(p - 1) \cdot (q - 1)$ and both options for e$e$ satisfy 饾憭 < 位(n)$饾憭 < 位(n)$.
Are there any other things iI need to consider for e$e$ to answer the question, hints? I have looked around the forum and web but I'm stuck right now.
Hints preferred not a full answer!