How can a cyclic group have two generators?
I believe part of the difficulty you are running into is because, in cryptography, we use the word 'generator' in multiple distinct (albeit related) ways.
One meaning (which is what is intended here) is this: we say that an element $g$ is a generator for a group $G$ if the group of elements $\{ g^0, g^1, g^2, ... \}$ is precisely the group $G$; that is, every element $h \in G$ can be expressed as $h = g^i$ for some $i$, and conversely, for every $i$, $g^i \in G$ [1].
Now, the obvious question is: for a given cyclic [2] group $G$, is the choice of $g$ unique? It turns out that (as long as the order of the group is > 2) it is not. In fact (as mentioned in the comments), if the size of the group is prime, then every group element (other than the identity) happens to generate the entire group, and so (in this sense) there are also generators.
Now, to give you some perspective, I will give you another meaning we give 'generator' that isn't meant by this question. Sometimes, in a cryptographic protocol, we need to specify a public generator $g$ that will be used by both sides. A simple example of this is Diffie-Hellman, where one side computes and publishes $g^a$, and the other side computes and publishes $g^b$; both sides must use the same $g$ value for this to work. We call this common value the generator; yes, there are other values that are (in the first meaning) also generators for the group we're working in, however, they are not the generator as far as protocol is concerned.
[1]: for infinite groups, we also need to consider negative exponents; we don't worry about infinite groups that much in cryptography.
[2]: actually, the definition of a cyclic group essentially is "there exists a generator"
