1
$\begingroup$

Actually, I want to know whether there are explicit and formal definitions of the properties which are authenticity, integrity or non-repudiation.

It seems that the signatures and MACs can achieve the authenticity, integrity, non-repudiation and unforgeability. However, there is only an unforgeable experiment when we consider the security of signatures or MACs.

Q1: What about other three types of security experiments? Are there the formal definitions of the security experiments of the other three properties?

Q2: What are the relations among these four properties? (Anyway, how to prove the relation formally, if there are not a formal definitions?)

If the unforgeability implies the others which means that unforgeability is the strongest notion among these four properties, then I think I can regard this conclusion as the answer of Q1. If any pair of these four properties are separated, there must exist a scheme which only achieves any part of these four properties. (I know that a scheme which cannot achieve all these four properties is not secure. I just want to consider the existence of them in order to know the relation among these four properties.)

$\endgroup$
3
  • $\begingroup$ Are you interested in the relation ship between the security properties the algorithms achieve, or the functioning of the algorithms from the inside? I suggest restructure the question to make the separation clear. $\endgroup$
    – DannyNiu
    Commented Apr 9, 2020 at 2:24
  • $\begingroup$ @DannyNiu The first one I think, let me modify it. $\endgroup$
    – Blanco
    Commented Apr 10, 2020 at 3:14
  • $\begingroup$ Typos: integrality should be integrity; ungorgebility should be unforgeability. $\endgroup$
    – fgrieu
    Commented Sep 7, 2020 at 17:02

2 Answers 2

2
$\begingroup$

One thing I'd like to point out clearly is that MAC is not a digital signature. MACs offer authenticity and integrality, but not non-repudiation. MACs are generated using shared secret (symmetric key). Non-repudation can be discussed only in the context of public key cryptography.

$\endgroup$
0
$\begingroup$

The 3 properties have commonly accepted meaning in Cryptography:

  • Authenticity: The message comes from the party associated with the verification key.

  • Integrity: The message had not been modified.

  • Non-repudiation: The signer cannot deny themselves signing the message.

We usually model the security against the weakest point of the signature/MAC - being forged; whereas other types of attacks such as key-recovery automatically implies the algorithm is insecure.

The unforgeability implies the other 3 (2 in case of MAC) properties, because the ability to forge a signature/MAC under a particular algorithm implies that

  1. the message may come from someone capable of forging the signagure/MAC (authenticity),

  2. capable of modifying a signed message (integrity), and

  3. capable of signing messages against the wish of the holder of the private key (non-repudiation).

$\endgroup$
4
  • $\begingroup$ Do you mean that the unforgeability is the weakest one? As you say, if a signature/MAC is not unforgeability (someone has the ability to forge it), then it cannot achieve any one of other 3 properties. In other words, if it achieves any one of these 3 properiies, the it also achieves unforgeability. $\endgroup$
    – Blanco
    Commented Apr 10, 2020 at 5:35
  • $\begingroup$ I mean forgery is often the cheapest aspect of a signature/MAC to attack. A signature/MAC has to achieve all of the 3/2 properties to be unforgeable. $\endgroup$
    – DannyNiu
    Commented Apr 10, 2020 at 10:48
  • $\begingroup$ But the security game only captures the unforgeability, which means that a unforgeabe signature/MAC may not achieve other properties. How can we prove or guarantee that a unforgeabe signature/MAC also achieves other 3/2 properties. $\endgroup$
    – Blanco
    Commented Apr 10, 2020 at 12:50
  • $\begingroup$ @TeamBright "How can we prove or guarantee" - through simple reasoning of course. If you firmly question such reasoning, I'll be glad if you can demonstrate its flaw, empirically, logically, or by citing a reference. $\endgroup$
    – DannyNiu
    Commented Apr 13, 2020 at 1:39

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.